Python Pandas - Return a new Timedelta with seconds floored resolution

To return a new Timedelta floored to this resolution, use the timedelta.floor() method. For seconds floored resolution, set the freq parameter to the value S.

At first, import the required libraries −

import pandas as pd

TimeDeltas is Python’s standard datetime library uses a different representation timedelta’s. Create a Timedelta object

timedelta = pd.Timedelta('4 days 11 hours 38 min 20 s 35 ms 55 ns')

Display the Timedelta

print("Timedelta...\n", timedelta)

Return the floored Timestamp with seconds floored resolution

timedelta.floor(freq='S')

Example

Following is the code

import pandas as pd

# TimeDeltas is Python’s standard datetime library uses a different representation timedelta’s
# create a Timedelta object
timedelta = pd.Timedelta('4 days 11 hours 38 min 20 s 35 ms 55 ns')

# display the Timedelta
print("Timedelta...\n", timedelta)

# return the floored Timestamp
# with seconds floored resolution
res = timedelta.floor(freq='S')

# display the floored Timestamp
print("\nTimedelta (seconds floored)...\n", res)

Output

This will produce the following code

Timedelta...
4 days 11:38:20.035000055

Timedelta (seconds floored)...
4 days 11:38:20