To round the Timedelta with specified resolution, use the timestamp.round() method. Set the seconds frequency resolution using the freq parameter with value ‘s’.
At first, import the required libraries −
import pandas as pd
Create a Timedelta object −
timedelta = pd.Timedelta('1 days 11 hours 22 min 25 s 50 ms 45 ns')
Display the Timedelta −
print("Timedelta...\n", timedelta)
Return the rounded Timestamp with seconds frequency. Here, the specified resolution is set using the "freq" parameter: −
timedelta.round(freq='s')
Example
Following is the code −
import pandas as pd # TimeDeltas is Python’s standard datetime library uses a different representation timedelta’s # create a Timedelta object timedelta = pd.Timedelta('1 days 11 hours 22 min 25 s 50 ms 45 ns') # display the Timedelta print("Timedelta...\n", timedelta) # return the rounded Timestamp # with seconds frequency # Here, the specified resolution is set using the "freq" parameter res = timedelta.round(freq='s') # display the rounded Timestamp print("\nTimedelta (seconds rounded)...\n", res)
Output
This will produce the following code −
Timedelta... 1 days 11:22:25.050000045 Timedelta (seconds rounded)... 1 days 11:22:25