In this article, we will learn about the solution to the problem statement given below.
Problem statement − We are given a string, we need to find the occurrence of each character in a given string.
Here we will be discussing 3 approaches as discussed below:L
Approach 1 − The brute-force approach
Example
test_str = "Tutorialspoint"
#count dictionary
count_dict = {}
for i in test_str:
#for existing characters in the dictionary
if i in count_dict:
count_dict[i] += 1
#for new characters to be added
else:
count_dict[i] = 1
print ("Count of all characters in Tutorialspoint is :\n "+
str(count_dict))Output
Count of all characters in Tutorialspoint is :
{'T': 1, 'u': 1, 't': 2, 'o': 2, 'r': 1, 'i': 2, 'a': 1, 'l': 1, 's': 1, 'p': 1, 'n': 1}Approach 2 − Using the collections module
Example
from collections import Counter
test_str = "Tutorialspoint"
# using collections.Counter() we generate a dictionary
res = Counter(test_str)
print ("Count of all characters in Tutorialspoint is :\n "+
str(dict(res)))Output
Count of all characters in Tutorialspoint is :
{'T': 1, 'u': 1, 't': 2, 'o': 2, 'r': 1, 'i': 2, 'a': 1, 'l': 1, 's': 1, 'p': 1, 'n': 1}Approach 3 − Using set() in a lambda expression
Example
test_str = "Tutorialspoint"
# using set() to calculate unique characters in the given string
res = {i : test_str.count(i) for i in set(test_str)}
print ("Count of all characters in Tutorialspoint is :\n "+
str(dict(res)))Output
Count of all characters in Tutorialspoint is :
{'T': 1, 'u': 1, 't': 2, 'o': 2, 'r': 1, 'i': 2, 'a': 1, 'l': 1, 's': 1, 'p': 1, 'n': 1}Conclusion
In this article, we have learned about how we can find the occurrence of each character in a given string.