php-java-bridge-users Mailing List for PHP/Java Bridge

Hello!

   1.  function toString() {return "helloWorld";};
   2.  $object =
java_closure<http://php-java-bridge.sourceforge.net/pjb/docs/php-api/java/_JavaProxy.inc.html#functionjava_closure>
   ();
   3.  echo "Java says that PHP says: $object\n";
In this example, no arguments are passed in the java_closure() function.
What does java_closure() transform? 


The current environment. 


   1.  function hello() {return "hello";};
   2.  echo (string)java_closure<http://php-java-bridge.sourceforge.net/pjb/docs/php-api/java/_JavaProxy.inc.html#functionjava_closure>
   (null, "hello");

In this example, I think the function hello() is transformed,

The current environment, which all its procedures renamed to "hello".

  The manual talks
about a keymap: maybe give an example? 
Why is the first argument null?

java_closure(null, array("foo"=>"hello"));

maps "foo" calls to "hello" procedures of the current environment.



You are looking for:

java_closure($phpObj, null, array(java("my.Interface1"), java("my.Interface2")...));


Peter



      

Hi,

java_closure reifies an environment for java. It needs a signature.

It does not make attributes available. Those are availabe through methods
declared in the interface.

This explains the error message: You have tried to change a non-existent
attribute. It failed. And the next set! tried to modify the failure report.

Regards,
Jost Bökemeier

Thanks for the answer.

IMHI, the manual about java_closure() is not always obvious.

ex:

   1.  function toString() {return "helloWorld";};
   2.  $object =
java_closure<http://php-java-bridge.sourceforge.net/pjb/docs/php-api/java/_JavaProxy.inc.html#functionjava_closure>
   ();
   3.  echo "Java says that PHP says: $object\n";

In this example, no arguments are passed in the java_closure() function.
What does java_closure() transform? Only the last object? It is not clear in
the manual.

ex:

   1.  function hello() {return "hello";};
   2.  echo (string)java_closure<http://php-java-bridge.sourceforge.net/pjb/docs/php-api/java/_JavaProxy.inc.html#functionjava_closure>
   (null, "hello");

In this example, I think the function hello() is transformed, because
"hello" is the second argument. It is a good idea, to change the first line
in ... return "helloWorld";}; to prevent confusion with the second argument
of java_closure() (PHP developpers are KISS-thinkers :-)). The manual talks
about a keymap: maybe give an example? Why is the first argument null?

Now, for my case.

What is $input?

In PHP two classes are declared:
class encodeRequest {
    /**
     * @var string
     */
    public $applicationName;
    /**
     * @var array[1, unbounded] of (object)OriginalDataType
     */
    public $originalData;
}

class OriginalDataType {
    /**
     * @var string
     */
    public $id;
    /**&;
     * @var boolean
     */
    public $randomize;
    /**
     * @var string
     */
    public $inputData;
}

$data = new OriginalDataType();
$data->id = 1;
$data->randomize= false;
$data->inputData = "blabla";

$input = new encodeRequest();
$input->applicationName = "WWM";
$input->originalData = $data;

So $input is an instance of the encodeRequest class. I want this PHP
instance be transformed in a Java instance.

I thought that $java_input = java_closure($input); would do the trick?

Sincerely,

Koen


2011/2/24 <php...@li...>

> Hi,
>
> > 1. I don't understand the remark:
> > "Your java object backed by a php
> > instance doesn't have any public methods."
>
> It's a java.lang.Object which implements no interfaces. Not very
> useful unless your library detects that it is a proxy and directly
> calls its invocation handler. Please see the java_closure() API for
> details at
> http://php-java-bridge.sourceforge.net/pjb/docs/php-api/java/_JavaProxy.inc.html#functionjava_closure
>
> > public static Object[] encode(Object request) throws RuntimeException,
> > Exception {
> >
> > -> I added static: that was logic
> > -> I added RuntimeException, like in the FAQ.
>
> In this case your code will work and I have no explanation for this
> issue either.
>
> But if your library is smart enough to call $java_input's invocation
> handler, please have a look at your PHP code called from the
> invocation handler. It probably calls a library method which throws an
> unchecked exception.
>
> The problem is simply that an unchecked exception has been returned
> from a Java call but not thrown. (You can get around this by setting
> JAVA_PREFER_VALUES, but I think you know that).
>
>
> Be it as it may, if you only want to add a sec header to your soap
> request, you can do this in PHP as well. Or implement it in Java and
> call the entire method from PHP.
>
>
> Regards,
> Jost Bökemeier
>
>
> ------------------------------------------------------------------------------
> Free Software Download: Index, Search & Analyze Logs and other IT data in
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> php...@li...
> https://lists.sourceforge.net/lists/listinfo/php-java-bridge-users
>



-- 
*Koen Thomeer*, MD, MSc
http://koen.thomeer.be

Hi,

> 1) Is it mandatory for the PHP script to be hosted on a web server?

PHP uses a reference counter which cannot collect some cycles. So yes.
PHP runs best when invoked from a WEB-Server or as a scriptlet from a
Java application.

> Can I pass a database connection to PHP

Sure.

Regards,
Jost Bökemeier

Hi,

> 1. I don't understand the remark:
> "Your java object backed by a php
> instance doesn't have any public methods."

It's a java.lang.Object which implements no interfaces. Not very
useful unless your library detects that it is a proxy and directly
calls its invocation handler. Please see the java_closure() API for
details at http://php-java-bridge.sourceforge.net/pjb/docs/php-api/java/_JavaProxy.inc.html#functionjava_closure

> public static Object[] encode(Object request) throws RuntimeException,
> Exception {
>
> -> I added static: that was logic
> -> I added RuntimeException, like in the FAQ.

In this case your code will work and I have no explanation for this
issue either.

But if your library is smart enough to call $java_input's invocation
handler, please have a look at your PHP code called from the
invocation handler. It probably calls a library method which throws an
unchecked exception.

The problem is simply that an unchecked exception has been returned
from a Java call but not thrown. (You can get around this by setting
JAVA_PREFER_VALUES, but I think you know that).


Be it as it may, if you only want to add a sec header to your soap
request, you can do this in PHP as well. Or implement it in Java and
call the entire method from PHP.


Regards,
Jost Bökemeier

Hi,

I'm brand new to the bridge and just exploring what my options. In my
scenario, I would be using JSR223 to execute PHP script from within Java. I
have two questions:

1) Is it mandatory for the PHP script to be hosted on a web server? Can I
just load it from the file system and execute evaluate it?
2) Can I pass a database connection to PHP? With RhinoJS and JSR223, I can
initiate a socket connection in Java and pass it to Javascript where it gets
used without problem. Can I do the same with the Java/PHP bridge?

Thanks,
Muesli.

Hi,

please see our FAQ entry "Does it support PHP 4?" at
http://php-java-bridge.sourceforge.net/pjb/FAQ.html


Regards,
Jost Bökemeier

Many thanks for the help!

1. I don't understand the remark:
"Your java object backed by a php
instance doesn't have any public methods."
=> the method is public (but I did forget the 'static').

2. I changed the code of java:

public static Object[] encode(Object request) throws RuntimeException,
Exception {

-> I added static: that was logic
-> I added RuntimeException, like in the FAQ.

But the error stays the same...

2011/2/24 <php...@li...>

> Hi,
>
> your java code has thrown an unchecked exception (error or runtime
> exception). After that your php code has tried to set a non-existing
> property on it.
>
> Any unchecked exception crossing the container boundary must be declared,
> otherwise the behaviour is undefined. Please see our FAQ for details.
>
> Your code contains several problems. Your java object backed by a php
> instance doesn't have any public methods. This may or may not be what you
> want. And you call a method as if it were a procedure. Won't work, so I
> assume that the code you have shown isn't the code you actually use. Either
> encode is actually static or the php code you have posted is missing a new
> statement.
>
> Regards,
> Jost Bökemeier
>
> ------------------------------------------------------------------------------
> Free Software Download: Index, Search & Analyze Logs and other IT data in
> Real-Time with Splunk. Collect, index and harness all the fast moving IT
> data
> generated by your applications, servers and devices whether physical,
> virtual
> or in the cloud. Deliver compliance at lower cost and gain new business
> insights. http://p.sf.net/sfu/splunk-dev2dev
> _______________________________________________
> php-java-bridge-users mailing list
> php...@li...
> https://lists.sourceforge.net/lists/listinfo/php-java-bridge-users
>



-- 
*Koen Thomeer*, MD, MSc
http://koen.thomeer.be

Hello All,

I am facing issue with java bridge 4.1.8  for php 4.3.9 with jdk 1.5.0_15.
It was working for PHP 5.x perfectly. The service is not getting
initialized. Java is running. The  Let me know how to fix it...

Cheers,

*Niju Mohan,*

I am out of the office until 02/24/2011.




Note: This is an automated response to your message
"[Php-java-bridge-users] CXF webservice with PHP: Couldn't execute
method java_InternalException" sent on 2/23/2011 3:26:18 PM.

This is the only notification you will receive while this person is away.

Hi,

your java code has thrown an unchecked exception (error or runtime
exception). After that your php code has tried to set a non-existing
property on it.

Any unchecked exception crossing the container boundary must be declared,
otherwise the behaviour is undefined. Please see our FAQ for details.

Your code contains several problems. Your java object backed by a php
instance doesn't have any public methods. This may or may not be what you
want. And you call a method as if it were a procedure. Won't work, so I
assume that the code you have shown isn't the code you actually use. Either
encode is actually static or the php code you have posted is missing a new
statement.

Regards,
Jost Bökemeier

Hello,

I'm new at php-java-bridge (and in java).

I made a class in Java CXF to invoke a webservice with ws-security
(something that is difficult in PHP).

The class is the following in short:

package be.icthealth.ehealth;

import org.apache.log4j.BasicConfigurator;
import org.apache.log4j.Logger;
import org.apache.log4j.Level;
import org.apache.ws.security.handler.WSHandlerConstants;
import org.apache.cxf.endpoint.dynamic.DynamicClientFactory;
import org.apache.cxf.ws.security.wss4j.WSS4JOutInterceptor;
import org.apache.cxf.endpoint.Client;
import java.util.HashMap;
import java.util.Map;
import java.io.File;
import java.net.URL;
//import java.lang.reflect.Method;

/**
 *
 * @author Koen Thomeer, MD, http://koen.thomeer.be
 */
public class Codage {

    /**
     * @param request the class EncodeRequest
     * @return response the class Response
     * @throws Exception
     */
    public Object[] encode(Object request) throws Exception {
        //throw new Exception("test");
        // configure logging
        BasicConfigurator.configure();
        Logger.getLogger("org").setLevel(Level.WARN);

java.util.logging.Logger.getLogger("").setLevel(java.util.logging.Level.WARNING);


        //code that I did leave out//

        // call the Codage
        Object[] response = client.invoke("encode", request);
        return response;
    }
}

The PHP code to call is the following (in short, it is nested in a function;
$input is a PHP Instance):

define("JAVA_PREFER_VALUES", false);
require_once("http://localhost:8080/JavaBridgeWS/java/Java.inc");
try {
$Codage = java("be.icthealth.ehealth.Codage");
$java_input = java_closure($input);
$java_output = $Codage->encode($java_input);
$output = java_values($java_output);
print_r($output);
    } catch (JavaException $e) {
        // in case of an error, process the fault
        echo $e;
    }

The error in the HTTPD log is the following:

[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP Fatal error:
Couldn't execute method java_InternalException::__set in Unknown on line 0
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP Stack trace:
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP   1. {main}()
/project/wmailer-test/www/secure/test/codage_test.php:0
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP   2.
EH_encode() /project/wmailer-test/www/secure/test/codage_test.php:5
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP   3.
JavaClass->encode() /project/wmailer-test/www/secure/test/codage5.php:219
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP   4.
Java->__call() http://localhost:8080/JavaBridgeWS/java/Java.inc:0
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP   5.
java_AbstractJava->__call()
http://localhost:8080/JavaBridgeWS/java/Java.inc:1999
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP   6.
java_JavaProxy->__call()
http://localhost:8080/JavaBridgeWS/java/Java.inc:1851
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP   7.
java_Client->invokeMethod()
http://localhost:8080/JavaBridgeWS/java/Java.inc:1752
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP   8.
java_Client->getResult()
http://localhost:8080/JavaBridgeWS/java/Java.inc:560
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP   9.
java_Client->getWrappedResult()
http://localhost:8080/JavaBridgeWS/java/Java.inc:366
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP  10.
java_Arg->getResult() http://localhost:8080/JavaBridgeWS/java/Java.inc:360
[Wed Feb 23 22:17:37 2011] [error] [client 84.196.244.172] PHP  11.
java_ThrowExceptionProxyFactory->checkResult()
http://localhost:8080/JavaBridgeWS/java/Java.inc:235

Questions:
1. What I'm doing wrong? I don't understand the log.
2. Where I've to put the keystore, properties file, etc?

Thx,

Koen


-- 
*Koen Thomeer*, MD, MSc
http://koen.thomeer.be

Hi John,

it doesn't matter if you require Java.inc indirectly via Apache/Tomcat
or directly from the ../JavaBridge/java/ directory. The result is all
the same.


Regards,
Jost Bökemeier

On Tue, Jan 25, 2011 at 1:58 AM, <
php...@li...> wrote:

> Hi,
>
> the cache-control HTTP header can be used to allow caching for a certain
> time.
>
> Not sure why you think that require'ing a local php file may cause
> problems.
>

Jost,

My concern was that Java.inc wasn't just a static file, but rather had code
generated dynamically via JSP or something like that.  I don't know all the
details of the Bridge's inner workings.  I looked through the file and
didn't see anything like that, so seemed pretty safe to me.



> Regards,
> Jost Bökemeier
>
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>



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