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Hi Nicolas,

Nicolas Mailhot wrote:
> 
> Le Mar 9 juillet 2013 15:14, Nicolas Mailhot a écrit :
>>
>> Le Lun 8 juillet 2013 18:18, Martin Mokrejs a écrit :
> 
>>> Could you instead just test for "if not self._family"? Tests for
>>> equality
>>> are more expensive (that means self._family == 0 or self._family ==
>>> False
>>> will also trigger your return).
>>
>> I can test if it works. However, all the other tests in that file are
>> already of the if Foo is None form, and I didn't want to change the coding
>> style

I think it is a bad style then. If in some places a '' or False
is needed to discriminate from None then the code should be changed.


> 
> And I can confirm the following patch also fixes my workload
> 
> diff -uNr matplotlib-1.2.1.orig/lib/matplotlib/font_manager.py
> matplotlib-1.2.1/lib/matplotlib/font_manager.py
> --- matplotlib-1.2.1.orig/lib/matplotlib/font_manager.py        2013-03-26
> 14:04:37.000000000 +0100
> +++ matplotlib-1.2.1/lib/matplotlib/font_manager.py     2013-07-08
> 14:49:37.791845661 +0200
> @@ -721,6 +721,8 @@
>          Return the name of the font that best matches the font
>          properties.
>          """
> +        if not self._family:
> +          return rcParams['font.family'][0]
>          return ft2font.FT2Font(str(findfont(self))).family_name
> 
>      def get_style(self):
> 
> Now could something similar be merged?


Thank you for your efforts on this. I am just a user like you so we have to
wait for an answer of the maintainers. Maybe I should have emphasized that earlier.
;-) But this is good for the community review anyway. ;)

Martin

Le Mar 9 juillet 2013 15:14, Nicolas Mailhot a écrit :
>
> Le Lun 8 juillet 2013 18:18, Martin Mokrejs a écrit :

>> Could you instead just test for "if not self._family"? Tests for
>> equality
>> are more expensive (that means self._family == 0 or self._family ==
>> False
>> will also trigger your return).
>
> I can test if it works. However, all the other tests in that file are
> already of the if Foo is None form, and I didn't want to change the coding
> style

And I can confirm the following patch also fixes my workload

diff -uNr matplotlib-1.2.1.orig/lib/matplotlib/font_manager.py
matplotlib-1.2.1/lib/matplotlib/font_manager.py
--- matplotlib-1.2.1.orig/lib/matplotlib/font_manager.py        2013-03-26
14:04:37.000000000 +0100
+++ matplotlib-1.2.1/lib/matplotlib/font_manager.py     2013-07-08
14:49:37.791845661 +0200
@@ -721,6 +721,8 @@
         Return the name of the font that best matches the font
         properties.
         """
+        if not self._family:
+          return rcParams['font.family'][0]
         return ft2font.FT2Font(str(findfont(self))).family_name

     def get_style(self):

Now could something similar be merged?

Regards,

-- 
Nicolas Mailhot

Le Lun 8 juillet 2013 18:18, Martin Mokrejs a écrit :
> Nicolas Mailhot wrote:
>> Hi,
>>
>> In matplotlib 1.2.1, the  get_name function is not garding against none
>> self (unlike other functions); Unfortunately it seems I have a workload
>> that makes matplotlib call get_name with None (wasn't the case in
>> 1.2.0).
>> I couldn't isolate the exact trigger, when I reduce the volume of data
>> processed the problem goes away so I have to simple shareable
>> reproducer.
>>
>> Anyway, the following patch makes it all work for me, could it (or
>> something similar) be merged?
>>
>> diff -uNr matplotlib-1.2.1.orig/lib/matplotlib/font_manager.py
>> matplotlib-1.2.1/lib/matplotlib/font_manager.py
>> --- matplotlib-1.2.1.orig/lib/matplotlib/font_manager.py
>> 2013-03-26
>> 14:04:37.000000000 +0100
>> +++ matplotlib-1.2.1/lib/matplotlib/font_manager.py     2013-07-08
>> 14:49:37.791845661 +0200
>> @@ -721,6 +721,8 @@
>>          Return the name of the font that best matches the font
>>          properties.
>>          """
>> +        if self._family is None:
>> +          return rcParams['font.family']
>>          return ft2font.FT2Font(str(findfont(self))).family_name
>>
>>      def get_style(self):
>>
>> Regards,
>>
>
> Could you instead just test for "if not self._family"? Tests for equality
> are more expensive (that means self._family == 0 or self._family == False
> will also trigger your return).

I can test if it works. However, all the other tests in that file are
already of the if Foo is None form, and I didn't want to change the coding
style

Regards,

-- 
Nicolas Mailhot

The violinplots  look amazing, that is what I was looking for, thanks!!

Carlos


------------------------------------------
Carlos


On Mon, Jul 8, 2013 at 10:57 PM, <jos...@gm...> wrote:

> On Mon, Jul 8, 2013 at 4:36 PM, Benjamin Root <ben...@ou...> wrote:
> > This looks very similar to something Tony Yu made once.  Check out this
> > thread:
> >
> >
> http://matplotlib.1069221.n5.nabble.com/Combination-of-a-box-plot-and-a-histogram-td25313.html#a25319
> >
> > Note that Tony now has some sort of toolbox available that may have some
> of
> > this implemented easily.
>
> and some variations on the violins made it into statsmodels
>
>
> http://statsmodels.sourceforge.net/devel/generated/statsmodels.graphics.boxplots.violinplot.html
>
> http://statsmodels.sourceforge.net/devel/generated/statsmodels.graphics.boxplots.beanplot.html
>
> Josef
>
> >
> > Cheers!
> > Ben Root
> >
> >
> >
> > On Mon, Jul 8, 2013 at 4:19 PM, Carlos Becker <car...@gm...>
> > wrote:
> >>
> >> Hi all,
> >>
> >> I was wondering if there is something similar to this
> >> http://reference.wolfram.com/mathematica/ref/DistributionChart.html in
> >> matplotlib, or if someone can give me a hint on how to implement it,
> since
> >> it is very interesting for density plots.
> >>
> >> As far as I saw, there are histogram plots already available in
> >> matplotlib, but I haven't seen something close to what is shown in the
> link
> >> above.
> >>
> >> Thanks,
> >>
> >> ------------------------------------------
> >> Carlos
> >>
> >>
> >>
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06.07.2013, 16:23, "Ryan Nelson":
> You might need to explicitly specify your axes object rather than
> relying on plt.subplot.
> Try replacing 'ax = plt.sublplot(111)' with 'ax = plt.axes([0, 0, 1, 1])'.

Ryan, thanks for your reply
Your suggestion works perfectly

Cheers

Hello there,

I would like to have a plot with centered axes (spines) and also "boxed"
with possible (major and minor) tickmarks along the borders of the visible
box. The usual examples from matplotlib gallery only deal with borderless
centered/zeroed spines; I would rather have a mix of the second ("normal
spines") and third ("centered spines") or fourth ("zeroed spines") plots in
the matplotlib spine placement demo page
(http://matplotlib.org/examples/pylab_examples/spine_placement_demo.html).

Thanks for any help

PS: sorry if this message appears more than once, since I got confused with
the nabble and matplotlib-users options/subscriptions



--
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