diff options
| author | Tom Lane | 2023-02-07 16:56:43 +0000 |
|---|---|---|
| committer | Tom Lane | 2023-02-07 16:56:43 +0000 |
| commit | 2cbbffff05b853733ae19ca7047cfeb9a346a497 (patch) | |
| tree | 45cab0c8d474b288b4d6c6d91cb100f52752726d /src/test/regress | |
| parent | aa6954104644334c53838f181053b9f7aa13f58c (diff) | |
The initial "put back OJ relids" adjustment of ojscope was
incorrect and unnecessary; it seems to be a leftover from
when I (tgl) was trying to get this function to work at all.
Richard Guo
Discussion: https://postgr.es/m/CAMbWs4-L2C47ZGZPabBAi5oDZsKmsbvhYcGCy5o=gCjsaG_ZQA@mail.gmail.com
Diffstat (limited to 'src/test/regress')
| -rw-r--r-- | src/test/regress/expected/join.out | 26 | ||||
| -rw-r--r-- | src/test/regress/sql/join.sql | 15 |
2 files changed, 41 insertions, 0 deletions
diff --git a/src/test/regress/expected/join.out b/src/test/regress/expected/join.out index 07f5aad5ea..eea8978fad 100644 --- a/src/test/regress/expected/join.out +++ b/src/test/regress/expected/join.out @@ -4982,6 +4982,32 @@ select id from a where id in ( -> Seq Scan on b (5 rows) +-- check optimization with oddly-nested outer joins +explain (costs off) +select a1.id from + (a a1 left join a a2 on true) + left join + (a a3 left join a a4 on a3.id = a4.id) + on a2.id = a3.id; + QUERY PLAN +------------------------------ + Nested Loop Left Join + -> Seq Scan on a a1 + -> Materialize + -> Seq Scan on a a2 +(4 rows) + +explain (costs off) +select a1.id from + (a a1 left join a a2 on a1.id = a2.id) + left join + (a a3 left join a a4 on a3.id = a4.id) + on a2.id = a3.id; + QUERY PLAN +------------------ + Seq Scan on a a1 +(1 row) + -- check that join removal works for a left join when joining a subquery -- that is guaranteed to be unique by its GROUP BY clause explain (costs off) diff --git a/src/test/regress/sql/join.sql b/src/test/regress/sql/join.sql index 7157b5cccc..9d20b88d71 100644 --- a/src/test/regress/sql/join.sql +++ b/src/test/regress/sql/join.sql @@ -1770,6 +1770,21 @@ select id from a where id in ( select b.id from b left join c on b.id = c.id ); +-- check optimization with oddly-nested outer joins +explain (costs off) +select a1.id from + (a a1 left join a a2 on true) + left join + (a a3 left join a a4 on a3.id = a4.id) + on a2.id = a3.id; + +explain (costs off) +select a1.id from + (a a1 left join a a2 on a1.id = a2.id) + left join + (a a3 left join a a4 on a3.id = a4.id) + on a2.id = a3.id; + -- check that join removal works for a left join when joining a subquery -- that is guaranteed to be unique by its GROUP BY clause explain (costs off) |