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A Belated Welcome!

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Sorry for the belated welcome, but the cookies are still warm!

Here's wishing you a belated welcome to Wikipedia, Agor153. I see that you've already been around awhile and wanted to thank you for your contributions. Though you seem to have been successful in finding your way around, you may benefit from following some of the links below, which help one get the most out of Wikipedia. If you have any questions, feel free to leave me a message on my talk page or by typing {{helpme}} at the bottom of this page. I love to help new users, so don't be afraid to leave a message! I hope you like the place and decide to stay. Here are some pages that you might find helpful:

I hope you enjoy editing here and being a Wikipedian! Also, when you post on talk pages you should sign your name on talk pages using four tildes (~~~~); that should automatically produce your username and the date after your post. If you need help, check out Wikipedia:Questions, ask me on my talk page, or place {{helpme}} on your talk page and ask your question there. Again, welcome! --Ser Amantio di NicolaoChe dicono a Signa?Lo dicono a Signa. 20:37, 27 August 2010 (UTC)[reply]

Thank you for the very tasty cookies! --Agor153 (talk) 19:16, 30 August 2010 (UTC)[reply]

Just wanted to thank you for the nice work on the detailed balance page! My academic advisor and I were both very impressed. Matty j (talk) 18:43, 3 April 2012 (UTC)[reply]

Thank you, Matty, for the kind words and corrections. Your correction of the misprint in the semi-detailed balance formula demonstrates that you fully understand the subject, indeed.-Agor153 (talk) 20:12, 7 April 2012 (UTC)[reply]

Gas vs Fluid

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I thought a gas was considered a fluid. Not that I have a problem with relabelling the animation to a less general case. The bit "just compare the mean free path to the distance between particles" escapes me, could you explain? Cheers, Peter (Southwood) (talk): 07:54, 5 June 2012 (UTC)[reply]

Gas is very different from liquid. One of the simple diagnostic properties is in the relation between three parameters: the size of particles, the distance between them and the mean free path. In a liquid they are close to each other. If you see a media where distance is larger than size and free mean path is larger than distance then it is not a fluid, it is a gas. (For the normal conditions, you have to expect, very roughly, the ratio 1:10:100.) Liquid is much more "crowdy". Another difference between gas and liquid is in the local correlations. They exist in liquid and are obviously absent on the illustration. -Agor153 (talk) 10:43, 5 June 2012 (UTC)[reply]
BTW, just for the future discussion, the mean free path concept of diffusion has no serious relations to diffusion in liquids.-Agor153 (talk) 10:47, 5 June 2012 (UTC)[reply]
One more, lexical problem. In the general lexicon, "fluid" could stand for "liquid or gas", but in physical literature it stands mainly for "liquid". This is not a difference of concepts, just a tradition.-Agor153 (talk) 10:55, 5 June 2012 (UTC) To check this statement I tried "gas and fluid separation" in GOOGLe. There are >250,000 links (nevertheless, some dictionaries stress that "fluid" means gas and liquid, indeed).-Agor153 (talk) 12:06, 5 June 2012 (UTC)[reply]
Well there you go; as an engineer I would have said if it flows, it is fluid, and if it stays in a cup under acceleration it is a liquid.
Also not clear on "local correlations", would this be local forces between the particles which would affect their trajectories, so they would not typically travel in straight lines, or something else? Cheers, Peter (Southwood) (talk): 18:33, 5 June 2012 (UTC)[reply]
About correlations, see for example, Fig 1 in a very well known paper (more than 1000 citations) G. Kresse and J. Hafner, Ab initio molecular dynamics for liquid metals, Phys. Rev. B, 47 (1) (1993), 558-561. The local structure of a liquid is much closer to solids than to gases (roughly speaking). Therefore, the elementary kinetic models based on the mean free path do not describe diffusion in liquids and the illustration with the motion of gas has no relation to diffusion of liquid.-Agor153 (talk) 21:28, 5 June 2012 (UTC) BTW, a nice example of the correlation function in liquid is given here: Radial distribution function-Agor153 (talk) 21:35, 5 June 2012 (UTC) Travelling of particles in a liquid cannot be modelled by straight lines or deformed straight lines. Particles there are oscillating near a temporary "equilibrium" position and sometimes jump to the nearest defect (free volume). There is nothing like free flight from one collision to another collision as it goes in a gas._Agor153 (talk) 21:44, 5 June 2012 (UTC)[reply]
Thanks, I will take a look later, it sounds quite interesting. Peter (Southwood) (talk): 05:41, 6 June 2012 (UTC)[reply]

I responded to a post you gave, hope it clarifies things. If I'm wrong could you please advise on what is the correct mathematical definition of flux using consistent notation? Thank you, z = + c 15:22, 18 July 2012 (UTC)[reply]

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Concerning the work of Aizik Volpert in mathematical chemistry

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Hi Agor153, I noticed your contributions to the entry about Aizik Isaakovich Vol'pert, including the nice picture you uploaded, and I wonder if you know other sources giving informations concerning his activity as a chemical engineer/mathematical chemist. Do you have further information/references? I'm trying to improve the entry. Best regards, Daniele.tampieri (talk) 17:30, 19 May 2013 (UTC)[reply]

Fine, I will prepare several referencces with a "mini-review" in a week or so. Thank you.Agor153 (talk) 22:47, 19 May 2013 (UTC)[reply]
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Please see my note under talk on the diffusion page

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I'm sure that you have the best intentions in being an editor, but your efforts on the diffusion page will be incredibly damaging for school students.

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Content you added to the above article appears to have been copied from https://doi.org/10.1016/j.cell.2019.01.006, which is not released under a compatible license. Copying text directly from a source is a violation of Wikipedia's copyright policy. Unfortunately, for copyright reasons, some content had to be removed. Also, you included material from this paper, available under a Creative Commons Attribution 4.0 International License. That's okay, but you have to give attribution so that our readers are made aware that you copied the prose rather than wrote it yourself. I've added the attribution for this instance. Please make sure that you follow this licensing requirement when copying from compatibly-licensed material in the future. Please leave a message on my talk page if you have any questions. — Diannaa 🍁 (talk) 10:53, 10 August 2019 (UTC)[reply]

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