Python program to return rows that have element at a specified index

When it is required to return rows that have an element at a specified index, a simple iteration and the ‘append’ function can be used.

Example

Below is a demonstration of the same

my_list_1 = [[21, 81, 35], [91, 14, 0], [64, 61, 42]]
my_list_2 = [[21, 92, 63], [80, 19, 65], [54, 65, 36]]

print("The first list is :")
print(my_list_1)
print("The second list is :")
print(my_list_2)
my_key = 0

my_result = []
for index in range(len(my_list_1)):

   if my_list_1[index][my_key] == my_list_2[index][my_key]:
      my_result.append(my_list_1[index])
      my_result.append(my_list_1[index])

print("The result is :")
print(my_result)

Output

The first list is :
[[21, 81, 35], [91, 14, 0], [64, 61, 42]]
The second list is :
[[21, 92, 63], [80, 19, 65], [54, 65, 36]]
The result is :
[[21, 81, 35], [21, 81, 35]]

Explanation

• Two nested lists are defined and are displayed on the console.

• A key, i.e index value is defined.

• An empty list is defined.

• The first list is iterated over, and if the indices of the first and second index elements match, the value is appended to the empty list.

• This is the result that is displayed on the console.