Suppose we have a numeric string s. We have to check whether there is some arrangement where we can have one pair of the same character and the rest of the string form any number of triplets of the same characters.
So, if the input is like s = "21133123", then the output will be True, because there are two 2s to form "22" as the pair and "111", "333" as two triplets.
To solve this, we will follow these steps −
d := a list containing frequencies of each elements present in s
for each k in d, do
d[k] := d[k] - 2
if d[i] mod 3 is 0 for all i in d, then
return True
d[k] := d[k] + 2
return False
Example
Let us see the following implementation to get better understanding
from collections import Counter def solve(s): d = Counter(s) for k in d: d[k] -= 2 if all(d[i] % 3 == 0 for i in d): return True d[k] += 2 return False s = "21133123" print(solve(s))
Input
"21133123"
Output
True