To return an IntervalArray identical to the current one but closed on the left side, use the set_closed() method with value left.
At first, import the required libraries −
import pandas as pd
Create IntervalArray −
index = pd.arrays.IntervalArray.from_breaks(range(5))
Display the interval −
print("IntervalIndex...\n",index)
Return an IntervalArray identical to the current one but closed on specified side i.e. "left" here −
print("\nResult...",index.set_closed('left'))
Example
Following is the code −
import pandas as pd # Create IntervalArray index = pd.arrays.IntervalArray.from_breaks(range(5)) # Display the interval print("IntervalIndex...\n",index) # Display the interval length print("\nIntervalIndex length...\n",index.length) # the left bound print("\nThe left bound for the IntervalIndex...\n",index.left) # the right bound print("\nThe right bound for the IntervalIndex...\n",index.right) # Return an IntervalArray identical to the current one but closed on specified # side i.e. "left" here print("\nResult...",index.set_closed('left'))
Output
This will produce the following output −
IntervalIndex... <IntervalArray> [(0, 1], (1, 2], (2, 3], (3, 4]] Length: 4, dtype: interval[int64, right] IntervalIndex length... Int64Index([1, 1, 1, 1], dtype='int64') The left bound for the IntervalIndex... Int64Index([0, 1, 2, 3], dtype='int64') The right bound for the IntervalIndex... Int64Index([1, 2, 3, 4], dtype='int64') Result... <IntervalArray> [[0, 1), [1, 2), [2, 3), [3, 4)] Length: 4, dtype: interval[int64, left]