To return an IntervalArray identical to the current one but closed on the specified side, use the set_closed() method with parameter set as both.
At first, import the required libraries −
import pandas as pd
Create IntervalArray −
index = pd.arrays.IntervalArray.from_breaks(range(6))
Display the interval −
print("IntervalIndex...\n",index)Return an IntervalArray identical to the current one but closed on specified side i.e. "both" here −
print("\nResult...",index.set_closed('both'))
Example
Following is the code −
import pandas as pd
# Create IntervalArray
index = pd.arrays.IntervalArray.from_breaks(range(6))
# Display the interval
print("IntervalIndex...\n",index)
# Display the interval length
print("\nIntervalIndex length...\n",index.length)
# the left bound
print("\nThe left bound for the IntervalIndex...\n",index.left)
# the right bound
print("\nThe right bound for the IntervalIndex...\n",index.right)
# Return an IntervalArray identical to the current one but closed on specified
# side i.e. "both" here
print("\nResult...",index.set_closed('both'))Output
This will produce the following output −
IntervalIndex... <IntervalArray> [(0, 1], (1, 2], (2, 3], (3, 4], (4, 5]] Length: 5, dtype: interval[int64, right] IntervalIndex length... Int64Index([1, 1, 1, 1, 1], dtype='int64') The left bound for the IntervalIndex... Int64Index([0, 1, 2, 3, 4], dtype='int64') The right bound for the IntervalIndex... Int64Index([1, 2, 3, 4, 5], dtype='int64') Result... <IntervalArray> [[0, 1], [1, 2], [2, 3], [3, 4], [4, 5]] Length: 5, dtype: interval[int64, both]