To return the rule code applied on the given BusinessDay object, use the BusinessDay.rule_code property in Pandas.
At first, import the required libraries −
import datetime import pandas as pd
Set the timestamp object in Pandas −
timestamp = pd.Timestamp('2021-10-30 01:55:02.000045')
Create the BusinessDay Offset. BusinessDay is the DateOffset subclass −
bdOffset = pd.tseries.offsets.BusinessDay(offset = datetime.timedelta(hours = 8, minutes = 10))
Display the Updated Timestamp −
print("\nUpdated Timestamp...\n",timestamp + bdOffset)
Return the rule code of the frequency applied on the given BusinessDay Offset −
print("\nThe rule code of the BusinessDay object..\n", bdOffset.rule_code)
Example
Following is the code −
import datetime import pandas as pd # Set the timestamp object in Pandas timestamp = pd.Timestamp('2021-10-30 01:55:02.000045') # Display the Timestamp print("Timestamp...\n",timestamp) # Create the BusinessDay Offset # BusinessDay is the DateOffset subclass bdOffset = pd.tseries.offsets.BusinessDay(offset = datetime.timedelta(hours = 8, minutes = 10)) # Display the BusinessDay Offset print("\nBusinessDay Offset...\n",bdOffset) # Display the Updated Timestamp print("\nUpdated Timestamp...\n",timestamp + bdOffset) # return the frequency applied on the given BusinessDay object as a string print("\nFrequency on the given BusinessDay Offset...\n",bdOffset.freqstr) # return the rule code of the frequency applied on the given BusinessDay Offset print("\nThe rule code of the BusinessDay object..\n", bdOffset.rule_code)
Output
This will produce the following code −
Timestamp... 2021-10-30 01:55:02.000045 BusinessDay Offset... <BusinessDay: offset=datetime.timedelta(seconds=29400)> Updated Timestamp... 2021-11-01 10:05:02.000045 Frequency on the given BusinessDay Offset... B+8H10Min The rule code of the BusinessDay object.. B