^ | # Beginning of string |
(?! | # Do not match if |
|2{1,2}5) | # Or there is one or two 2s followed by a 5 |
.* | # Anything else is accepted |
Example
The following code fulfils the conditions in given question
import re foo = '2249678' foo2 = '2259678' result = re.findall(r'^(?!2{1,2}5).*', foo) result2 = re.findall(r'^(?!2{1,2}5).*', foo2) print result print result2
Output
This gives the output
['2249678'] []