Using RegEx module is the fastest way.
>>> import re
Assuming that the string contains integer and floating point numbers as well as below −
>>> s='my age is 25. I have 55.50 percent marks and 9764135408 is my number'
the findall() function returns a list of numbers matching given pattern which includes digit before and after decimal point
>>> re.findall('\d*\.?\d+',s)Result is a list object of all numbers
['25', '55.50', '9764135408']