Python Program for Find sum of odd factors of a number

In this article, we will learn about the solution to the problem statement given below −

Problem statement

Given a number input n, the task is to Find the sum of odd factors of a number.

Here we first need to eliminate all the even factors.

To remove all even factors, we repeatedly divide n till it is divisible by 2. After this step, we only get the odd factors of the number.

Below is the implementation −

Example

import math
def sumofoddFactors( n ):
   #prime factors
   res = 1
   # ignore even factors
   while n % 2 == 0:
      n = n // 2
   for i in range(3, int(math.sqrt(n) + 1)):
      count = 0
      curr_sum = 1
      curr_term = 1
      while n % i == 0:
         count+=1
         n = n // i
         curr_term *= i
         curr_sum += curr_term
      res *= curr_sum
   # n is a prime number.
   if n >= 2:
      res *= (1 + n)
      return res
# main
n = 27
print(sumofoddFactors(n))

Output

41

All the variables are declared in the global frame as shown in the figure given below −

Conclusion

In this article, we learnt about the approach to Find sum of odd factors of a number