Suppose we have one year Y and a month M, we have to return the number of days of that month for the given year. So if the Y = 1992 and M = 7, then the result will be 31, if the year is 2020, and M = 2, then the result is 29.
To solve this, we will follow these steps −
- if m = 2, then
- if y is a leap year, return 29, otherwise 28
- make an array with elements [1,3,5,7,8,10,12]
- if m is in the list, then return 31, otherwise, return 30.
Example(Python)
Let us see the following implementation to get a better understanding −
class Solution(object): def numberOfDays(self, y, m): leap = 0 if y% 400 == 0: leap = 1 elif y % 100 == 0: leap = 0 elif y% 4 == 0: leap = 1 if m==2: return 28 + leap list = [1,3,5,7,8,10,12] if m in list: return 31 return 30 ob1 = Solution() print(ob1.numberOfDays(2020, 2))
Input
2020 2
Output
29