In this tutorial, we are going to write a program that finds the index of a sublist element from the list. Let's see an example to understand it clearly.
Input
nested_list = [[1, 2, 3], [4, 5], [6, 7, 8, 9]]
Output
Index of 7:- 2 Index of 5:- 1 Index of 3:- 0
Let's see the simple and most common way to solve the given problem. Follow the given steps solve it.
- Initialize the list.
- Iterate over the list using the index.
- Iterate over the sub list and check the element that you want to find the index.
- If we find the element then print and break it
Example
# initializing the lit
nested_list = [[1, 2, 3], [4, 5], [6, 7, 8, 9]]
# function to find the index
def index(element):
# initializing a flag for tracking the element
is_found = False
# iterating over the list
for i in range(len(nested_list)):
# iterating over the sub list
for j in range(len(nested_list[i])):
# cheking for the element
if nested_list[i][j] == element:
# printing the sub list index that contains the element
print(f'Index of {element}: {i}')
# changing the flag to True
is_found = True
# breaking the inner loop
break
# breaking the outer loop
if is_found:
break
# checking whether the element is found or not
if not is_found:
# printing the element not found message
print("Element is not present in the list")
index(7)
index(5)
index(3)Output
If you run the above code, then you will get the following result.
Index of 7: 2 Index of 5: 1 Index of 3: 0
Conclusion
If you have any queries regarding the tutorial, mention them in the comment section