Suppose we have a string that is representing a 12-hour clock time with suffix am or pm, and an integer n is also given, we will add n minutes to the time and return the new time in the same format.
So, if the input is like s = "8:20pm" and n = 150, then the output will be 10:50pm
To solve this, we will follow these steps −
h, m := take the hour and minute part from s
h := h mod 12
if the time s is in 'pm', then
h := h + 12
t := h * 60 + m + n
h := quotient of t/60, m := remainder of t/60
h := h mod 24
suffix := 'am' if h < 12 otherwise 'pm'
h := h mod 12
if h is same as 0, then
h := 12
return the time h:m suffix
Let us see the following implementation to get better understanding −
Example
class Solution:
def solve(self, s, n):
h, m = map(int, s[:-2].split(':'))
h %= 12
if s[-2:] == 'pm':
h += 12
t = h * 60 + m + n
h, m = divmod(t, 60)
h %= 24
suffix = 'a' if h < 12 else 'p'
h %= 12
if h == 0:
h = 12
return "{:02d}:{:02d}{}m".format(h, m, suffix)
ob = Solution()
print(ob.solve("8:20pm", 150))Input
"8:20pm", 150
Output
10:50pm