Suppose we have a robot, that is currently sitting in at position (0, 0) (Cartesian plane). If we have list of its moves that it can make, containing N(North), S(South), W(West), and E(East). We have to check whether it can reach at destination coordinate (x, y).
So, if the input is like moves = ['N','N','E','E','S'], (x,y) = (2,1), then the output will be True,
To solve this, we will follow these steps −
- temp_coord := [0,0]
- for each move in moves, do
- if move is same as "N", then
- temp_coord[1] := temp_coord[1] + 1
- otherwise when move is same as "S", then
- temp_coord[1] := temp_coord[1] - 1
- otherwise when move is same as "E", then
- temp_coord[0] := temp_coord[0] + 1
- otherwise when move is same as "W", then
- temp_coord[0] := temp_coord[0] - 1
- if move is same as "N", then
- return True when temp_coord[0] is same as coord[0] and temp_coord[1] is same as coord[1] otherwise false.
Let us see the following implementation to get better understanding −
Example
class Solution: def solve(self, moves, coord): temp_coord = [0,0] for move in moves: if move == "N": temp_coord[1] += 1 elif move == "S": temp_coord[1] -= 1 elif move == "E": temp_coord[0] += 1 elif move == "W": temp_coord[0] -= 1 return temp_coord[0] == coord[0] and temp_coord[1] == coord[1] ob = Solution() moves = ['N','N','E','E','S'] coord = [2,1] print(ob.solve(moves, coord))
Input
['N','N','E','E','S'], [2,1]
Output
True