Suppose we have a string s containing brackets parenthesis "(" and ")", we have to find the length of the longest subsequence of balanced brackets.
So, if the input is like s = "())(()(", then the output will be 4, as we can take the subsequence like "()()"
To solve this, we will follow these steps −
res := 0
n := size of s
close := 0
for i in range n - 1 to 0, decrease by 1, do
if s[i] is same as ")", then
close := close + 1
otherwise,
if close > 0, then
close := close - 1
res := res + 2
return res
Let us see the following implementation to get better understanding −
Example
class Solution:
def solve(self, s):
res = 0
n = len(s)
close = 0
for i in range(n - 1, -1, -1):
if s[i] == ")":
close += 1
else:
if close > 0:
close -= 1
res += 2
return res
ob = Solution()
s = "())(()("
print(ob.solve(s))Input
"())(()("Output
4