Suppose we have a number n. We have to check whether the mirror image of the number is same as the given number or not when it is displayed on Seven Segment display.
So, if the input is like n = 818, then the output will be True.
the mirror image is same.
To solve this, we will follow these steps −
- num_str := n as string
- for i in range 0 to size of num_str - 1, do
- if num_str[i] is not nay of ['0', '1', '8'] then, then
- return False
- if num_str[i] is not nay of ['0', '1', '8'] then, then
- left := 0
- right := size of num_str - 1
- while left < right, do
- if num_str[left] is not same as num_str[right], then
- return False
- left := left + 1
- right := right - 1
- if num_str[left] is not same as num_str[right], then
- return True
Example
Let us see the following implementation to get better understanding −
def solve(n): num_str = str(n) for i in range(len(num_str)): if num_str[i] not in ['0', '1', '8']: return False left = 0 right = len(num_str) - 1 while left < right: if num_str[left] != num_str[right]: return False left += 1 right -= 1 return True n = 818 print(solve(n))
Input
818
Output
True