Check if n is divisible by power of 2 without using arithmetic operators in Python

Suppose we have two numbers x and n. We have to check whether x is divisible by 2^n or not without using arithmetic operators.

So, if the input is like x = 32 n = 5, then the output will be True as 32 = 2^5.

To solve this, we will follow these steps −

• if x AND (2^n - 1) is 0, then
  • return True
• return False

Example

Let us see the following implementation to get better understanding −

def solve (x, n):
   if (x & ((1 << n) - 1)) == 0:
      return True
   return False
x = 32
n = 5
print(solve(x, n))

Input

32, 5

Output

True