Input −
Assume you have a series,
0 14 1 16 2 30 3 49 4 80
Output −
The result for perfect square elements are,
0 4 1 16 3 49
Solution 1
We can use regular expression and lambda function filter method to find the perfect square values.
Define a Series.
Apply lambda filter method to check the value is a perfect square or not. It is defined below,
l = [14,16,30,49,80] data=pd.Series([14,16,30,49,80]) result =pd.Series(filter(lambda x: x==int(m.sqrt(x)+0.5)**2,l))
Finally, check the list of values to the series using isin() function.
Example
import pandas as pd import math as m l = [4,16,30,49,80] data = pd.Series(l) print(data) lis = [] for i in range(len(data)): for j in data: if(data[i]==int(m.sqrt(j)+0.5)**2): lis.append(data[i]) print(“Perfect squares in the series: \n”, data[data.isin(lis)])
Output
Given series: 0 4 1 16 2 30 3 49 4 80 dtype: int64 Perfect Squares in the series: 0 4 1 16 3 49 dtype: int64
Solution 2
Example
import re import math as m l = [14,16,30,49,80] data = pd.Series([14,16,30,49,80]) print(“Given series:\n”, data) result = pd.Series(filter(lambda x: x==int(m.sqrt(x)+0.5)**2,l)) print(data[data.isin(result)])
Output
Given series: 0 14 1 16 2 30 3 49 4 80 dtype: int64 Perfect squares: 1 16 3 49 dtype: int64