For this, you can use IN() along with ORDER BY clause. Let us first create a table −
mysql> create table DemoTable1986 ( Number int ); Query OK, 0 rows affected (0.00 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1986 values(50); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1986 values(60); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1986 values(100); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1986 values(200); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1986 values(350); Query OK, 1 row affected (0.00 sec)
Display all records from the table using select statement −
mysql> select * from DemoTable1986;
This will produce the following output −
+--------+ | Number | +--------+ | 50 | | 60 | | 100 | | 200 | | 350 | +--------+ 5 rows in set (0.00 sec)
Here is the query to show specified id inside the IN clause −
mysql> select * from DemoTable1986 where Number IN(50,100,350) order by field(Number,350,100,50);
This will produce the following output −
+--------+ | Number | +--------+ | 350 | | 100 | | 50 | +--------+ 3 rows in set (0.00 sec)