For this, you can use the CASE statement along with SUM(). Here, we will be finding the count of Male and Female records from a column with employee gender values. Let us first create a table −
mysql> create table DemoTable ( EmployeeGender ENUM('Male','Female') ); Query OK, 0 rows affected (0.52 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable values('Male'); Query OK, 1 row affected (0.19 sec) mysql> insert into DemoTable values('Female'); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable values('Male'); Query OK, 1 row affected (0.10 sec) mysql> insert into DemoTable values('Female'); Query OK, 1 row affected (0.08 sec) mysql> insert into DemoTable values('Male'); Query OK, 1 row affected (0.07 sec) mysql> insert into DemoTable values('Female'); Query OK, 1 row affected (0.08 sec)
Display all records from the table using select statement −
mysql> select *from DemoTable;
This will produce the following output −
+----------------+ | EmployeeGender | +----------------+ | Male | | Female | | Male | | Female | | Male | | Female | +----------------+ 6 rows in set (0.00 sec)
Following is the query to get the count of two table fields in one query −
mysql> select sum(case when EmployeeGender='Male' then 1 else 0 end) as Total_Number_Of_Male_Employee, sum(case when EmployeeGender='Female' then 1 else 0 end) as Total_Number_Of_Female_Employee from DemoTable;
This will produce the following output −
+-------------------------------+---------------------------------+ | Total_Number_Of_Male_Employee | Total_Number_Of_Female_Employee | +-------------------------------+---------------------------------+ | 3 | 3 | +-------------------------------+---------------------------------+ 1 row in set (0.00 sec