Sort data for duplicate record in MySQL

Use ORDER BY to sort data for duplicate record.

Let us first create a table −

mysql> create table DemoTable788 (
   FirstName varchar(100),
   Score int
);
Query OK, 0 rows affected (1.89 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable788 values('Chris',78);
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable788 values('Robert',67);
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable788 values('Chris',98);
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable788 values('Chris',56);
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable788 values('Robert',43);
Query OK, 1 row affected (0.11 sec)
mysql> insert into DemoTable788 values('Robert',97);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable788 values('Chris',79);
Query OK, 1 row affected (0.12 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable788;

This will produce the following output -

+-----------+-------+
| FirstName | Score |
+-----------+-------+
| Chris     | 78    |
| Robert    | 67    |
| Chris     | 98    |
| Chris     | 56    |
| Robert    | 43    |
| Robert    | 97    |
| Chris     | 79    |
+-----------+-------+
7 rows in set (0.00 sec)

Following is the query to sort data for duplicate record. We are sorting data for duplicate name ‘Chris’ −

mysql> select Score from DemoTable788 where FirstName='Chris' order by Score DESC;

This will produce the following output -

+-------+
| Score |
+-------+
| 98    |
| 79    |
| 78    |
| 56    |
+-------+
4 rows in set (0.00 sec)