For this, you can use aggregate function SUM(). Let us first create a table −
mysql> create table DemoTable636 ( StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY,StudentFirstName varchar(100) ); Query OK, 0 rows affected (0.51 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable636(StudentFirstName) values('John'); Query OK, 1 row affected (0.18 sec) mysql> insert into DemoTable636(StudentFirstName) values('Robert'); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable636(StudentFirstName) values('Robert'); Query OK, 1 row affected (0.22 sec) mysql> insert into DemoTable636(StudentFirstName) values('Sam'); Query OK, 1 row affected (0.20 sec) mysql> insert into DemoTable636(StudentFirstName) values('Mike'); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable636(StudentFirstName) values('John'); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable636(StudentFirstName) values('Robert'); Query OK, 1 row affected (0.16 sec)
Display all records from the table using select statement −
mysql> select *from DemoTable636;
This will produce the following output −
+-----------+------------------+ | StudentId | StudentFirstName | +-----------+------------------+ | 1 | John | | 2 | Robert | | 3 | Robert | | 4 | Sam | | 5 | Mike | | 6 | John | | 7 | Robert | +-----------+------------------+ 7 rows in set (0.00 sec)
Following is the query to count occurrences of known (or enumerated) distinct values −
mysql> select sum(StudentFirstName='John') AS JOHN_COUNT, sum(StudentFirstName='Robert') AS ROBERT_COUNT, sum(StudentFirstName='Sam') AS SAM_COUNT, sum(StudentFirstName='Mike') AS MIKE_COUNT from DemoTable636;
This will produce the following output −
+------------+--------------+-----------+------------+ | JOHN_COUNT | ROBERT_COUNT | SAM_COUNT | MIKE_COUNT | +------------+--------------+-----------+------------+ | 2 | 3 | 1 | 1 | +------------+--------------+-----------+------------+ 1 row in set (0.00 sec)