For returned record set order, you need to use FIND_IN_SET() function.
For an example, let us create a table.
mysql> create table returnRecordSetOrderDemo -> ( -> Id int, -> Name varchar(20) -> ); Query OK, 0 rows affected (1.01 sec)
Insert some records in the table using insert command.
The query is as follows.
mysql> insert into returnRecordSetOrderDemo values(100,'John'); Query OK, 1 row affected (0.13 sec) mysql> insert into returnRecordSetOrderDemo values(130,'Carol'); Query OK, 1 row affected (0.13 sec) mysql> insert into returnRecordSetOrderDemo values(103,'Bob'); Query OK, 1 row affected (0.17 sec) mysql> insert into returnRecordSetOrderDemo values(134,'Sam'); Query OK, 1 row affected (0.27 sec) mysql> insert into returnRecordSetOrderDemo values(102,'Larry'); Query OK, 1 row affected (0.15 sec) mysql> insert into returnRecordSetOrderDemo values(145,'David'); Query OK, 1 row affected (0.18 sec)
Display all records from the table using select statement.
The query is as follows.
mysql> select *from returnRecordSetOrderDemo;
The following is the output.
+------+-------+ | Id | Name | +------+-------+ | 100 | John | | 130 | Carol | | 103 | Bob | | 134 | Sam | | 102 | Larry | | 145 | David | +------+-------+ 6 rows in set (0.00 sec)
Here is the query for MySQL 'IN' clause and the returned record set order.
mysql> select *from returnRecordSetOrderDemo -> where Id in(100,145,103,130) -> order by FIND_IN_SET(Id,'100,145,103,130');
The following is the output.
+------+------- | Id | Name | +------+-------+ | 100 | John | | 145 | David | | 103 | Bob | | 130 | Carol | +------+-------+ 4 rows in set (0.00 sec)