The field() function returns the index position of a value in a list of values. Let us sort the values using field() function with ORDER BY. The syntax is as follows.
SELECT *FROM yourTableName order by field(yourColumnName,yourValue1,yourValue2,yourValue3,yourValue4,.....N) desc;
To understand the above syntax, let us first create a table. The query to create a table is as follows.
mysql> create table OrderByDemo -> ( -> StudentId int -> ); Query OK, 0 rows affected (0.71 sec)
Insert some records in the table using insert command. The query is as follows.
mysql> insert into OrderByDemo values(101); Query OK, 1 row affected (0.19 sec) mysql> insert into OrderByDemo values(1010); Query OK, 1 row affected (0.56 sec) mysql> insert into OrderByDemo values(1001); Query OK, 1 row affected (0.12 sec) mysql> insert into OrderByDemo values(401); Query OK, 1 row affected (0.12 sec)
Now you can display all records from the table using select statement. The query is as follows.
mysql> select *from OrderByDemo;
The following is the output.
+-----------+ | StudentId | +-----------+ | 101 | | 1010 | | 1001 | | 401 | +-----------+ 4 rows in set (0.00 sec)
Here is the query to sort order by value. We will sort in descending order. The query is as follows.
mysql> select *from OrderByDemo order by field(StudentId,101,401,1001,1010) desc;
The following is the output.
+-----------+ | StudentId | +-----------+ | 1010 | | 1001 | | 401 | | 101 | +-----------+ 4 rows in set (0.00 sec)