You can achieve this with the help of update command. To understand the method, let us create a table. The query to create a table is as follows −
mysql> create table AddDateTimeWithOther −> ( −> Id int, −> IssueDate datetime, −> DueDate datetime −> ); Query OK, 0 rows affected (0.69 sec)
Insert some records in the table with insert statement. The query is as follows −
mysql> insert into AddDateTimeWithOther values(100,now(),date_add(now(),interval -3 year)); Query OK, 1 row affected (0.13 sec) mysql> insert into AddDateTimeWithOther values(101,now(),date_add(now(),interval 2 year)); Query OK, 1 row affected (0.20 sec)
Display all records from the table with the help of select statement. The query is as follows −
mysql> select *from AddDateTimeWithOther;
The following is the output −
+------+---------------------+---------------------+ | Id | IssueDate | DueDate | +------+---------------------+---------------------+ | 100 | 2018-12-11 17:33:28 | 2015-12-11 17:33:28 | | 101 | 2018-12-11 17:33:37 | 2020-12-11 17:33:37 | +------+---------------------+---------------------+ 2 rows in set (0.00 sec)
Now if you want to set some other date in place of “DueDate” ‘2015-12-11 17:33:28, then use the UPDATE command. The below query displays the same by updating the Due Date to ‘2019-12-11 17:35:03’.
The query is as follows −
mysql> update AddDateTimeWithOther set DueDate = date_add(now(),interval 1 year) where Id = 100; Query OK, 1 row affected (0.24 sec) Rows matched: 1 Changed: 1 Warnings: 0
Now you can check the data has been inserted or not. The query is as follows −
mysql> select *from AddDateTimeWithOther;
The following is the output displaying the update worked successfully and the date inserted −
+------+---------------------+---------------------+ | Id | IssueDate | DueDate | +------+---------------------+---------------------+ | 100 | 2018-12-11 17:33:28 | 2019-12-11 17:35:03 | | 101 | 2018-12-11 17:33:37 | 2020-12-11 17:33:37 | +------+---------------------+---------------------+ 2 rows in set (0.00 sec)