To display only the employee names with specific salaries, set the salaries in MongoDB $in and fetch the names. Let us create a collection with documents
> db.demo666.insertOne({"EmployeeName":"John","EmployeeSalary":25000});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ea1c04824113ea5458c7d0d")
}
> db.demo666.insertOne({"EmployeeName":"Chris","EmployeeSalary":35000});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ea1c05524113ea5458c7d0e")
}
> db.demo666.insertOne({"EmployeeName":"David","EmployeeSalary":65000});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ea1c06024113ea5458c7d0f")
}
> db.demo666.insertOne({"EmployeeName":"Carol","EmployeeSalary":40000});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ea1c06f24113ea5458c7d10")
}Display all documents from a collection with the help of find() method −
> db.demo666.find();
This will produce the following output −
{ "_id" : ObjectId("5ea1c04824113ea5458c7d0d"), "EmployeeName" : "John", "EmployeeSalary" : 25000 }
{ "_id" : ObjectId("5ea1c05524113ea5458c7d0e"), "EmployeeName" : "Chris", "EmployeeSalary" : 35000 }
{ "_id" : ObjectId("5ea1c06024113ea5458c7d0f"), "EmployeeName" : "David", "EmployeeSalary" : 65000 }
{ "_id" : ObjectId("5ea1c06f24113ea5458c7d10"), "EmployeeName" : "Carol", "EmployeeSalary" : 40000 }Following is the query to use $in and fetch the employee names with specific salaries −
> db.demo666.find({"EmployeeSalary":{$in:[35000,40000]}},{_id:0,"EmployeeSalary":0});This will produce the following output −
{ "EmployeeName" : "Chris" }
{ "EmployeeName" : "Carol" }