How to compare multiple properties in MongoDB?

To compare multiple properties, use $where in MongoDB. Let us create a collection with documents −

> db.demo223.insertOne({"Scores":[56,78]});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5e3ee4ca03d395bdc2134730")
}
> db.demo223.insertOne({"Scores":[88,45]});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5e3ee4d103d395bdc2134731")
}
> db.demo223.insertOne({"Scores":[98,79]});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5e3ee4d803d395bdc2134732")
}

Display all documents from a collection with the help of find() method −

> db.demo223.find();

This will produce the following output −

{ "_id" : ObjectId("5e3ee4ca03d395bdc2134730"), "Scores" : [ 56, 78 ] }
{ "_id" : ObjectId("5e3ee4d103d395bdc2134731"), "Scores" : [ 88, 45 ] }
{ "_id" : ObjectId("5e3ee4d803d395bdc2134732"), "Scores" : [ 98, 79 ] }

Following is the query to compare multiple properties in MongoDB −

> db.demo223.find({ $where : "this.Scores[0] > this.Scores[1]" });

This will produce the following output −

{ "_id" : ObjectId("5e3ee4d103d395bdc2134731"), "Scores" : [ 88, 45 ] }
{ "_id" : ObjectId("5e3ee4d803d395bdc2134732"), "Scores" : [ 98, 79 ] }