We are required to write a JavaScript function that takes in an array of integers as the only argument.
The function should sort the array based on the following conditions −
All even numbers are sorted in increasing order
All odd numbers are sorted in decreasing order
The relative positions of the even and odd numbers remain the same
For example −
If the input array is −
const arr = [12, 17, 15, 24, 1, 6];
Then the output should be −
const output = [6, 17, 15, 12, 1, 24];
Example
Following is the code −
const arr = [12, 17, 15, 24, 1, 6];
const specialSort = (nums = []) => {
const oddArr = [], evenArr = [];
for (let i = 0; i < nums.length; i++){
if (nums[i] & 1) {
oddArr.push(i);
} else {
evenArr.push(i);
}
}
nums.sort((a, b) => a - b);
let odd = oddArr.length - 1, even = 0;
const res = [];
for (let i = 0; i < nums.length; i++){
if (nums[i] & 1) {
res[oddArr[odd--]] = nums[i];
} else {
res[evenArr[even++]] = nums[i];
}
}
return res;
}Output
Following is the console output −
[ 6, 17, 15, 12, 1, 24 ]