In order to call the parent method when both parent and child have the same method name and signature.
You can use the below syntax −
console.log(yourParentClassName.prototype.yourMethodName.call(yourChildObjectName));
Example
class Super { constructor(value) { this.value = value; } display() { return `The Parent class value is= ${this.value}`; } } class Child extends Super { constructor(value1, value2) { super(value1); this.value2 = value2; } display() { return `${super.display()}, The Child Class value2 is=${this.value2}`; } } var childObject = new Child(10, 20); console.log("Calling the parent method display()=") console.log(Super.prototype.display.call(childObject)); console.log("Calling the child method display()="); console.log(childObject.display());
To run the above program, you need to use the following command −
node fileName.js.
Here, my file name is demo192.js.
Output
This will produce the following output −
PS C:\Users\Amit\javascript-code> node demo192.js Calling the parent method display()= The Parent class value is= 10 Calling the child method display()= The Parent class value is= 10, The Child Class value2 is=20