Regular Expression . (dot) Metacharacter in Java

The subexpression/metacharacter “.” matches any single character except a newline.

Example1

import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class MatchesAll {
   public static void main( String args[] ) {
      String regex = ".";
      String input = "Hi how are you welcome to Tutorialspoint";
      Pattern p = Pattern.compile(regex);
      Matcher m = p.matcher(input);
      int count = 0;
      while(m.find()) {
         count++;
      }
      System.out.println("Number of matches: "+count);
   }
}

Output

Number of matches: 40

Example 2

The following Java program accepts 5 strings from the user and prints the four-letter words ending with e.

import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class RegexExample {
   public static void main( String args[] ) {
      String regex = "...e";
      Scanner sc = new Scanner(System.in);
      System.out.println("Enter 5 input strings: ");
      String input[] = new String[5];
      for (int i=0; i<5; i++) {
         input[i] = sc.nextLine();
      }
      //Creating a Pattern object
      Pattern p = Pattern.compile(regex);
      System.out.println("four letter words that ends with e: ");
      for(int i=0; i<5;i++) {
         //Creating a Matcher object
         Matcher m = p.matcher(input[i]);
         if(m.matches()) {
            System.out.println(m.group());
         }
      }
   }
}

Output

Enter 5 input strings:
hive
sample
wife
life
naive
four letter words that ends with e:
hive
wife
life