The meta character “.” in java regular expression matches any character (single) it could be the alphabet, number or, any special character.
Example 1
import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class Example { public static void main(String args[]) { //Reading String from user System.out.println("Enter a String"); Scanner sc = new Scanner(System.in); String input = sc.nextLine(); //Regular expression to match any character String regex = "."; //Compiling the regular expression Pattern pattern = Pattern.compile(regex); //Retrieving the matcher object Matcher matcher = pattern.matcher(input); int count = 0; while(matcher.find()) { count ++; } System.out.println("Given string contains "+count+" characters."); } }
Output
Enter a String hello how are you welcome to tutorialspoint Given string contains 42 characters.
You can match any 3 characters between a and b using the following regular expression −
a…b
Similarly the expression “.*” matches n number of characters.
Example 2
Following Java program reads 5 strings from the user and accepts those which starts with b, ends with a with any number of characters in between them.
import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class RegexExample { public static void main( String args[] ) { String regex = "^b.*a$"; Scanner sc = new Scanner(System.in); System.out.println("Enter 5 input strings: "); String input[] = new String[5]; for (int i=0; i<5; i++) { input[i] = sc.nextLine(); } //Creating a Pattern object Pattern p = Pattern.compile(regex); for(int i=0; i<5;i++) { //Creating a Matcher object Matcher m = p.matcher(input[i]); if(m.find()) { System.out.println(input[i]+": accepted"); } else { System.out.println(input[i]+": not accepted"); } } } }
Output
Enter 5 input strings: barbara boolean baroda ram raju barbara: accepted boolean: not accepted baroda: accepted ram: not accepted raju: not accepted