In this article, we will understand how to check whether the input number is a neon number. A neon number is such a number whose sum of digits of square of the number is equal to the number.
Below is a demonstration of the same −
Input
Suppose our input is −
9
Output
The desired output would be the following because 92 = 81 i.e. 8 + 1 = 9
The given input is a neon number
Algorithm
Step1- Start Step 2- Declare an integers my_input Step 3- Prompt the user to enter an integer value/ Hardcode the integer Step 4- Read the values Step 5- Compute the square of the input and store it in a variable input_square Step 6- Compute the sum of the of the digits of input_square and compare the result with my_input Step 6- If the input matches, then the input number is a neon number Step 7- If not, the input is not a neon number. Step 8- Display the result Step 9- Stop
Example 1
Here, the input is being entered by the user based on a prompt. You can try this example live in ourcoding ground tool .
import java.util.Scanner; public class NeonNumbers{ public static void main(String[] args){ int my_input, input_square, sum=0; Scanner my_scanner = new Scanner(System.in); System.out.println("Required packages have been imported"); System.out.println("A scanner object has been defined "); System.out.println("Enter the number: "); my_input=my_scanner.nextInt(); input_square=my_input*my_input; while(input_square>0){ sum=sum+input_square%10; input_square=input_square/10; } if(sum!=my_input) System.out.println("The given input is not a Neon number."); else System.out.println("The given input is Neon number."); } }
Output
Required packages have been imported A scanner object has been defined Enter the number: 9 The given input is Neon number.
Example 2
Here, the integer has been previously defined, and its value is accessed and displayed on the console.
public class NeonNumbers{ public static void main(String[] args){ int my_input, input_square, sum=0; my_input= 9; System.out.printf("The number is %d ", my_input); input_square=my_input*my_input; while(input_square<0){ sum=sum+input_square%10; input_square=input_square/10; } if(sum!=my_input) System.out.println("\nThe given input is not a Neon number."); else System.out.println("\nThe given input is Neon number."); } }
Output
The number is 9 The given input is Neon number.