To fetch the consecutive 1’s, use the Bitwise Left Shift Operator. Here is our decimal number.
i = (i & (i << 1));
Loop the above until the value of I is 0 and fetch the length using a variable; count here.
while (i != 0) {
i = (i & (i << 1));
count++;
}The example we have taken here is 150.
The binary for 150 is 10010110. Therefore, we have two consecutive one’s.
Example
using System;
class Demo {
private static int findConsecutive(int i) {
int count = 0;
while (i != 0) {
i = (i & (i < 1));
count++;
}
return count;
}
// Driver code
public static void Main() {
// Binary or 150 is 10010110
Console.WriteLine(findConsecutive(150));
}
}Output
2