We shall develop a C++ program to implement Gift Wrapping Algorithm in two dimensions. The Gift Wrapping Algorithm is an algorithm for computing the convex hull of a given set of points.
Algorithm
Begin function convexHull() to find convex hull of a set of n points: There must be at least three points. Initialize the result. Find the leftmost point. Starting from leftmost point, keep moving counterclockwise until reach the start point again. Print the result. End
Example Code
#include <iostream>
using namespace std;
#define INF 10000
struct P {
int x;
int y;
};
int orient(P a, P b, P c) {
int v = (b.y - a.y) * (c.x - b.x) - (b.x - a.x) * (c.y - b.y);
if (v == 0)
return 0; // colinear
return (v >0) ? 1 : 2; // clock or counterclock wise
}
void convexHull(P points[], int m) {
if (m < 3)//at least three points required
return;
int n[m];
for (int i = 0; i < m; i++)
n[i] = -1;
int l = 0;//initialize result.
for (int i = 1; i < m; i++)
if (points[i].x < points[l].x)
l = i; //find left most point
int p = l, q;
do {
q = (p + 1) % m;
for (int i = 0; i < m; i++)
if (orient(points[p], points[i], points[q]) == 2)
q = i;
n[p] = q;
p = q;
} while (p != l);
for (int i = 0; i < m; i++) {
if (n[i] != -1)
cout << "(" << points[i].x << ", " << points[i].y << ")\n";
}
}
int main() {
P points[] = {{0, 4}, {2, 1}, {2, 3}, {4, 1}, {3, 0}, {1, 1}, {7, 6}};
cout << "The points in the convex hull are: ";
int n = sizeof(points) / sizeof(points[0]);
convexHull(points, n);
return 0;
}Output
The points in the convex hull are: (0, 4) (4, 1) (3, 0) (1, 1) (7, 6)