Prime Triplet in C++

In this problem, we are given a number N. Our task is to print all prime triplets less than N.

Prime triplet is a set of three prime numbers. That are of the form (p, p+2, p+6) or (p, p+4, p+6). All prime numbers are grouped according to the above triplets as every third prime in the direct pattern is a multiple of 6.

Let’s see an example to understand the problem

Input: N = 13
Output: 5 7 11

To solve this problem, we have to find all prime numbers less than equal to N. And the check for triplets.

The code to show the implementation of our solution,

Example

#include <bits/stdc++.h>
using namespace std;
void findPrimes(int n, bool prime[]) {
   for (int p = 2; p * p <= n; p++) {
      if (prime[p] == true) {
         for (int i = p * 2; i <= n; i += p)
         prime[i] = false;
      }
   }
}
void printPrimeTriplets(int n) {
   bool prime[n + 1];
   memset(prime, true, sizeof(prime));
   findPrimes(n, prime);
   for (int i = 2; i <= n-6; ++i) {
      if (prime[i] && prime[i + 2] && prime[i + 6])
         cout<<i<<"\t"<<(i+2)<<"\t"<<(i+6)<<endl;
      else if (prime[i] && prime[i + 4] && prime[i + 6])
         cout<<i <<"\t"<<(i + 4)<<"\t"<<(i + 6)<<endl;
   }
}
int main() {
   int N = 15;
   cout<<"Prime Triplets Less than "<<N<<" are :\n";
   printPrimeTriplets(N);
   return 0;
}

Output

Prime Triplets Less than 15 are :
5   7   11
7   11   13