Kth odd number in an array in C++

In this tutorial, we are going to write a program that finds the k-th odd number from the given array.

Let's see the steps to solve the problem.

• Initialise the array and k.
• Iterate over the array.
  • If the current element is odd, then decrement the value of k.
  • If k is 0, then return the current element.
• Return -1.

Example

Let's see the code.

#include <bits/stdc++.h>
using namespace std;
int findKthOddNumber(int arr[], int n, int k) {
   for (int i = 0; i <= n; i++) {
      if (arr[i] % 2 == 1) {
         k--;
      }
      if (k == 0) {
         return arr[i];
      }
   }
   return -1;
}
int main() {
   int arr[] = { 4, 5, 22, 1, 55 }, k = 3;
   cout << findKthOddNumber(arr, 5, k) << endl;
   return 0;
}

Output

If you run the above code, then you will get the following result.

55

Conclusion

If you have any queries in the tutorial, mention them in the comment section.