An array of integers is given. We have to find sum of all elements which are contiguous. Whose sum is largest, that will be sent as output.
Using dynamic programming we will store the maximum sum up to current term. It will help to find sum for contiguous elements in the array.
Input: An array of integers. {-2, -3, 4, -1, -2, 1, 5, -3} Output: Maximum Sum of the Subarray is : 7
Algorithm
maxSum(array, n)
Input − The main array, the size of the array.
Output − maximum sum.
Begin tempMax := array[0] currentMax = tempMax for i := 1 to n-1, do currentMax = maximum of (array[i] and currentMax+array[i]) tempMax = maximum of (currentMax and tempMax) done return tempMax End
Example
#include<iostream> using namespace std; int maxSum( int arr[], int n) { int tempMax = arr[0]; int currentMax = tempMax; for (int i = 1; i < n; i++ ) { //find the max value currentMax = max(arr[i], currentMax+arr[i]); tempMax = max(tempMax, currentMax); } return tempMax; } int main() { int arr[] = {-2, -3, 4, -1, -2, 1, 5, -3}; int n = 8; cout << "Maximum Sum of the Sub-array is: "<< maxSum( arr, n ); }
Output
Maximum Sum of the Sub-array is: 7