The challenge is to display the pattern using one loop only and with continue statement.
Algorith
START Step 1 -> declare start variables i and j to 0 with number of rows in n to 6 Step 2 -> Loop For i=1 and i<=n IF j<i Print * Increment j by 1 Continue End IF IF j=1 Print \n Set j=0 Increment i by 1 End IF Step 3 -> End For Loop STOP
Example
#include <stdio.h> int main() { int i, j=0; int n = 6; for ( i = 1; i <= n; ) { if( j < i ) { printf("*"); j++; continue; } if(j == i) { printf("\n"); j = 0; i++; } } return 0; }
Output
If we run above program then it will generate following output
* ** *** **** ***** ******