Given a number N we have to find the N-th even number.
Even numbers are the numbers which are completely divided by 2 and their remainder is zero. Like 2, 4, 6, 8, 10,….
If we closely observe the list of even numbers we can also represent them as
2*1=2, 2*2=4, 2*3=6, 2*4=8,….2*N.
So, to solve the problem we can simply multiply the number N with 2, so the result will be the number which is divisible by 2, i.e. the even number.
Example
Input: n = 4 Output: 8 The first 4 even numbers will be 2, 4, 6, 8, .. Input: n = 10 Output: 20
Algorithm
START STEP 1-> DECLARE AND SET n AS 10 STEP 2-> PRINT n*2 NUMBER STOP
Example
#include <stdio.h>
int main(int argc, char const *argv[]){
int n = 10;
printf("Nth even will be:%d", n*2);
return 0;
}Output
Nth even will be:20