In this problem, we are given a student’s record which contains student_id, student_name, student_percentage. Our task is to create a C program to store student records as structure and sort them by name.
Let’s take an example to understand the problem,
Input − student record =
{{ student_id = 1, student_name = nupur, student_percentage = 98}, { student_id = 2, student_name = Akash, student_percentage = 75}, { student_id = 3, student_name = Yash, student_percentage = 62}, { student_id = 4, student_name = Jyoti, student_percentage = 87}, { student_id = 5, student_name = Ramlal, student_percentage = 80}}
Output − student record =
{{ student_id = 2, student_name = Akash, student_percentage = 75}, { student_id = 4, student_name = Jyoti, student_percentage = 87}, { student_id = 1, student_name = nupur, student_percentage = 98}, { student_id = 5, student_name = Ramlal, student_percentage = 80}, { student_id = 3, student_name = Yash, student_percentage = 62}}
To solve this problem, we will first create a structure that will store the details of the student. Now, we will use qsort() and in that qsort, we will define a comparator function for this qsort that will compare the names of the structure using strcmp() method.
Example
The program to store Student records as Structures and Sort them by Name
//C program to store Student records as Structures and Sort them by Name #include <stdio.h> #include <stdlib.h> #include <string.h> struct Student { int student_id; char* student_name; int student_percentage; }; int comparator(const void* s1, const void* s2){ return strcmp(((struct Student*)s1)->student_name,((struct Student*)s2)->student_name); } int main() { int n = 5; struct Student arr[n]; //student 1 arr[0].student_id = 1; arr[0].student_name = "Nupur"; arr[0].student_percentage = 98; //student 2 arr[1].student_id = 2; arr[1].student_name = "Akash"; arr[1].student_percentage = 75; //student 3 arr[2].student_id = 3; arr[2].student_name = "Yash"; arr[2].student_percentage = 62; //student 4 arr[3].student_id = 4; arr[3].student_name = "Jyoti"; arr[3].student_percentage = 87; //student 5 arr[4].student_id = 5; arr[4].student_name = "Ramlal"; arr[4].student_percentage = 80; printf("Unsorted Student Record:\n"); for (int i = 0; i < n; i++) { printf("Id = %d, Name = %s, Age = %d \n", arr[i].student_id, arr[i].student_name, arr[i].student_percentage); } qsort(arr, n, sizeof(struct Student), comparator); printf("\n\nStudent Records sorted by Name:\n"); for (int i = 0; i < n; i++) { printf("Id = %d, Name = %s, Age = %d \n", arr[i].student_id, arr[i].student_name, arr[i].student_percentage); } return 0; }
Output
Unsorted Student Record: Id = 1, Name = Nupur, Age = 98 Id = 2, Name = Akash, Age = 75 Id = 3, Name = Yash, Age = 62 Id = 4, Name = Jyoti, Age = 87 Id = 5, Name = Ramlal, Age = 80 Student Records sorted by Name: Id = 2, Name = Akash, Age = 75 Id = 4, Name = Jyoti, Age = 87 Id = 1, Name = Nupur, Age = 98 Id = 5, Name = Ramlal, Age = 80 Id = 3, Name = Yash, Age = 62