Program to compare two fractions in C

Given two fractions with some numerator nume1 and nume2 and deno1 and deno2 as their respective denominator, the task is to compare both the fractions and find out the greater one. Like we have a fraction 1/2 and 2/3 and the higher one is 2/3 because the value of 1/2 is 0.5 and the value of 2/3 is 0.66667 which is higher.

Input 

first.nume = 2, first.deno = 3
second.nume = 4, second.deno = 3

Output 

4/3

Explanation 

2/3 = 0.66667 < 4/3 = 1.33333

Input 

first.nume = 1, first.deno = 2
second.nume = 4, second.deno = 3

Output 

4/3

Approach used below is as follows to solve the problem

//baadme likhunga

Algorithm

Start
Declare a struct Fraction with elements
   nume, deno
In function Fraction greater(Fraction first, Fraction sec)
   Step 1→ Declare and Initialize t Y = first.nume * sec.deno - first.deno *
sec.nume
   Step 2→ Return (Y > 0) ? first : sec
In function int main()
   Step 1→ Declare Fraction first = { 4, 5 }
   Step 2→Fraction sec = { 3, 4 }
   Step 3→ Fraction res = greater(first, sec)
   Step 4→ Print res.nume, res.deno
Stop

Example

#include <stdio.h>
struct Fraction {
   int nume, deno;
};
// Get max of the two fractions
Fraction greater(Fraction first, Fraction sec){
   //check if the result is in negative then the
   //second fraction is greater else first is greater
   int Y = first.nume * sec.deno - first.deno * sec.nume;
   return (Y > 0) ? first : sec;
}
int main(){
   Fraction first = { 4, 5 };
   Fraction sec = { 3, 4 };
   Fraction res = greater(first, sec);
   printf("The greater fraction is: %d/%d\n", res.nume, res.deno);
   return 0;
}

Output

If run the above code it will generate the following output −

The greater fraction is: 4/5