Given a number n, the task is to print the triangular patterns of alphabets of the length n. First print the n characters then decrement one from the beginning in each line.
The triangular pattern of alphabet will be like in the given figure below −
Input − n = 5
Output
Input − n = 3
Output
Approach used below is as follows to solve the problem
Take input n and loop i from 1 to n.
For every i iterate j from i to n for every j print a character subtract 1 and add the value of j to ‘A’ .
Algorithm
Start In function int pattern( int n) Step 1→ Declare int i, j Step 2→ Loop For i = 1 and i < n and i++ Loop For j = i and j <= n and j++ Print 'A' - 1 + j Print new line In function int main() Step 1→ Declare and initialize n = 5 Step 2→ call pattern(n) Stop
Example
#include <stdio.h> int pattern( int n){ int i, j; for (i = 1; i <= n; i++) { for (j = i; j <= n; j++) { printf("%c", 'A' - 1 + j); } printf("\n"); } return 0; } int main(){ int n = 5; pattern(n); return 0; }
Output
If run the above code it will generate the following output −