Problem
Calculate the sum and product of all elements in an array by using the run-time compilation.
Solution
A two-dimensional array is used in situations where a table of values have to be stored (or) in matrices applications
The syntax is as follows −
datatype array_ name [rowsize] [column size];
For example, int a[5] [5];
Number of elements in array = rowsize *columnsize = 5*5 = 25
Example
Following is the C program to calculate the sum and product of all elements in an array by using the run-time compilation −
#include<stdio.h> void main(){ //Declaring the array - run time// int A[2][3],B[2][3],i,j,sum[i][j],product[i][j]; //Reading elements into the array's A and B using for loop// printf("Enter elements into the array A: \n"); for(i=0;i<2;i++){ for(j=0;j<3;j++){ printf("A[%d][%d] :",i,j); scanf("%d",&A[i][j]); } printf("\n"); } for(i=0;i<2;i++){ for(j=0;j<3;j++){ printf("B[%d][%d] :",i,j); scanf("%d",&B[i][j]); } printf("\n"); } //Calculating sum and printing output// printf("Sum array is : \n"); for(i=0;i<2;i++){ for(j=0;j<3;j++){ sum[i][j]=A[i][j]+B[i][j]; printf("%d\t",sum[i][j]); } printf("\n"); } //Calculating product and printing output// printf("Product array is : \n"); for(i=0;i<2;i++){ for(j=0;j<3;j++){ product[i][j]=A[i][j]*B[i][j]; printf("%d\t",product[i][j]); } printf("\n"); } }
Output
When the above program is executed, it produces the following result −
Enter elements into the array A: A[0][0] :12 A[0][1] :23 A[0][2] :03 A[1][0] :25 A[1][1] :34 A[1][2] :01 B[0][0] :03 B[0][1] :46 B[0][2] :23 B[1][0] :01 B[1][1] :24 B[1][2] :32 Sum array is: 15 69 26 26 58 33 Product array is: 36 1058 69 25 816 32