Problem
How to write a C program to count numbers of vowels and consonants in a given string?
Solution
The logic that we will write to implement the code to find vowels and consonants is −
if(str[i] == 'A' || str[i] == 'E' || str[i] == 'I' || str[i] == 'O' || str[i] == 'U'||str[i] == 'a' || str[i] == 'e' || str[i] == 'i' || str[i] == 'o' || str[i] == 'u' )
If this condition is satisfied, we try to increment the vowels. Or else, we increment the consonants.
Example
Following is the C program to count the number of vowels and consonants in a string −
/* Counting Vowels and Consonants in a String */ #include <stdio.h> int main(){ char str[100]; int i, vowels, consonants; i = vowels = consonants = 0; printf("Enter any String\n : "); gets(str); while (str[i] != '\0'){ if(str[i] == 'A' || str[i] == 'E' || str[i] == 'I' || str[i] == 'O' || str[i] == 'U'||str[i] == 'a' || str[i] == 'e' || str[i] == 'i' || str[i] == 'o' || str[i] == 'u' ){ vowels++; } else consonants++; i++; } printf("vowels in this String = %d\n", vowels); printf("consonants in this String = %d", consonants); return 0; }
Output
When the above program is executed, it produces the following result −
Enter any String: TutoriasPoint vowels in this String = 6 consonants in this String = 7