Problem
For given number try to find the range in which that number exists.
Solution
Here, we are learning how to find the ranges of a number.
The logic that we apply to find range is −
lower= (n/10) * 10; /*the arithmetic operators work from left to right*/ upper = lower+10;
Explanation
Let number n=45
Lower=(42/10)*10 // division returns quotient
=4*10 =40
Upper=40+10=50
Range − lower-upper − 40-50
Example
Following is the C program for printing the range of numbers −
#include<stdio.h>
main(){
int n,lower,upper;
printf("Enter a number:");
scanf("%d",&n);
lower= (n/10) * 10; /*the arithmetic operators work from left to right*/
upper = lower+10;
printf("Range is %d - %d",lower,upper);
getch();
}Output
When the above program is executed, it produces the following result −
Enter a number:25 Range is 20 – 30
Here is another C program for printing the range of numbers.
#include<stdio.h>
main(){
int number,start,end;
printf("Enter a number:");
scanf("%d",&number);
start= (number/10) * 10; /*the arithmetic operators work from left to right*/
end = start+10;
printf("Range is %d - %d",start,end);
getch();
}Output
When the above program is executed, it produces the following result −
Enter a number:457 Range is 450 – 460